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Proof step 40 from proof ex-lst-shift (previous step)

rs1 ∩ rs0 = ∅, R[rs0, cf, af], xv(x)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ (o[_∃ xv] * R)[rs1 ∪ rs0, cf, af], ∃ x. xv(x)(mk(rs1, cf))

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: x

Additional information

Used terms: x