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Proof step 9 from proof ex-lst-shift (previous step)

rs1 ∩ rs0 = ∅, R[rs0, cf, af], (_∃ xv)(mk(rs1, cf)), ∀ r. r ∈ rs1 → af(r) = o ⊦ ∃ x. (o[xv(x)] * R)[rs1 ∪ rs0, cf, af]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information