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Proof step 3 from proof ls-fold1 (previous step)

((r => a × r0 * ls(r0, x) * P))(H) ⊦ ∃ r0. (((r => a × r0 * ls(r0, x)) * P))(H)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: r0

Additional information

Used simplifier rules: sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep Used terms: r0