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Proof step 2 from proof ls-unfold1 (
previous step
)
H[r] = ce ⊦ ((ls(r, x) * P))(H) ↔ (∃ a, y, r0. ((r => a × r0 * ls(r0, y) * P))(H) ∧ x = a ' + y), r = null
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
⊦ ((ls(r, x) * P))(H) ↔ (∃ a, y, r0. ((r => a × r0 * ls(r0, y) * P))(H) ∧ x = a ' + y), r = null
Rule argument
Additional information