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Proof step 7 from proof ls-unfold1 (previous step)

(((r => a0 × r0 * ls(r0, x0)) * P))(H) ⊦ r = null, ∃ a, y, r0. ((r => a × r0 * ls(r0, y) * P))(H) ∧ a0 ' + x0 = a ' + y

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: a0, x0, r0

Additional information

Used simplifier rules: sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep Used terms: a0, x0, r0