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Proof step 12 from proof owner-ls1 (
previous step
)
rs1 ∩ rs0 = ∅, R[rs0, cf, af], ls(r, x)(mk(rs1, cf)), r ∈ rs1 → af(r) = o ⊦ af(r) = o, r = null
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 13
:
rs1 ∩ rs0 = ∅, R[rs0, cf, af], ls(r, x)(mk(rs1, cf)) ⊦ af(r) = o, r = null, r ∈ rs1
Rule argument
Additional information