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Proof step 16 from proof owner-lst1 (previous step)

rs1 ∩ rs0 = ∅, ((r => a × r0 * ls(r0, x0)))(mk(rs1, cf)), R[rs0, cf, af], ∀ r. r ∈ rs1 → af(r) = o ⊦ af(r) = o, r = null

User applied rule all left

And obtained the following new goals

Proof step 17:
rs1 ∩ rs0 = ∅, ((r => a × r0 * ls(r0, x0)))(mk(rs1, cf)), R[rs0, cf, af], r ∈ rs1 → af(r) = o ⊦ af(r) = o, r = null

Rule argument

pos: left 4 terms: r abort: F discard: T computed: T

Additional information

Used terms: r