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Proof step 20 from proof owner-lst1 (previous step)

rs1 ∩ rs0 = ∅, R[rs0, cf, af], ∃ H0, H1. H0 ⊥ H1 ∧ mk(rs1, cf) = H0 ∪ H1 ∧ ((r => a × r0))(H0) ∧ ls(r0, x0)(H1) ⊦ af(r) = o, r = null, r ∈ rs1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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