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Proof step 3 from proof ll-trav1-init (previous step)

((lls(r0, null, x) * P))(H) ⊦ ∃ x0, x1. x = x0 + x1 ∧ ((lls(r0, r0, x0) * lls(r0, null, x1) * P))(H)

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: [], x abort: F discard: T computed: F

Additional information

Used simplifier rules: lls-base: ⊦ lls(r0, r1, []) = (emp ∧ ⌜r0 = r1⌝ );% ⊦ [] + x = x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ ⌜true⌝ = true; (s)% ⊦ (true ∧ P) = P; (s)%and-ass: ⊦ ((P0 ∧ P1) ∧ P2) = (P0 ∧ P1 ∧ P2); from specification heap-sep%and-com: ⊦ (P0 ∧ P1) = (P1 ∧ P0); from specification heap-sep% ⊦ emp * P = P; (s)%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep Used terms: [], x