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Proof step 5 from proof ll-trav2-end (
previous step
)
H[r2] = a × null, x = [], ((ll-trav(r0, r1, r2, x) * P))(H) ⊦ r2 = null
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
H[r2] = a × null, ((ll-trav(r0, r1, r2, []) * P))(H) ⊦ r2 = null
Rule argument
Additional information