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Proof step 3 from proof lls-consecutive (previous step)

((lls(r0, r1, x) * lls(r1, r2, y) * P))(H) ⊦ ((lls(r0, r2, x + y) * P))(H)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
((lls(r0, r1, a + x0) * lls(r1, r2, y) * P))(H), ∀ r0, r1, r2, y, P, H. ((lls(r0, r1, x0) * lls(r1, r2, y) * P))(H) → ((lls(r0, r2, x0 + y) * P))(H) ⊦ ((lls(r0, r2, (a + x0) + y) * P))(H)

Rule argument

indvar: x

Additional information

Used simplifier rules: lls-base: ⊦ lls(r0, r1, []) = (emp ∧ ⌜r0 = r1⌝ );%list freely generated by [], +;;% ⊦ (⌜bv⌝ ∧ P0) * P1 = (⌜bv⌝ ∧ P0 * P1); (s)% ⊦ emp * P = P; (s)%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep%and-ass: ⊦ ((P0 ∧ P1) ∧ P2) = (P0 ∧ P1 ∧ P2); from specification heap-sep%and-com: ⊦ (P0 ∧ P1) = (P1 ∧ P0); from specification heap-sep% ⊦ ((P0 ∧ P1))(H) ↔ P0(H) ∧ P1(H); (s)% ⊦ ⌜bv⌝ (H) ↔ bv; (s)% ⊦ [] + x = x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list