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Proof step 6 from proof lls-consecutive (previous step)

(((r0 => a × r * lls(r, r1, x0)) * lls(r1, r2, y) * P))(H), ((lls(r, r1, x0) * lls(r1, r2, y) * P * r0 => a × r))(H) → ((lls(r, r2, x0 + y) * P * r0 => a × r))(H), ∀ r0, r1, r2, y, P, H. ((lls(r0, r1, x0) * lls(r1, r2, y) * P))(H) → ((lls(r0, r2, x0 + y) * P))(H) ⊦ ∃ r. (((r0 => a × r * lls(r, r2, x0 + y)) * P))(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
(((r0 => a × r * lls(r, r1, x0)) * lls(r1, r2, y) * P))(H), ((lls(r, r2, x0 + y) * P * r0 => a × r))(H), ∀ r0, r1, r2, y, P, H. ((lls(r0, r1, x0) * lls(r1, r2, y) * P))(H) → ((lls(r0, r2, x0 + y) * P))(H) ⊦ ∃ r. (((r0 => a × r * lls(r, r2, x0 + y)) * P))(H)

Rule argument

Additional information

Used simplifier rules: eq-objs: ⊦ ((r => ce * P0))(H) ∧ ((r => ce0 * P1))(H) → ce = ce0; (forward) from specification maplet[cell-heap]%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep