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Proof step 2 from proof lls-fold-tail (
previous step
)
((r1 => x.last × r2 * lls(r0, r1, x.butlast) * P))(H) ⊦ x = [], ((lls(r0, r2, x) * P))(H)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
((r1 => x.last × r2 * lls(r0, r1, x.butlast) * P))(H) ⊦ x = [], ((lls(r0, r2, x) * P))(H)
Rule argument
Additional information