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Proof step 6 from proof lls-unfold-head (previous step)

∃ r. (((r0 => a0 × r * lls(r, r2, x0)) * P))(H) ⊦ ∃ a, y, r. ((r0 => a × r * lls(r, r2, y) * P))(H) ∧ a0 ' + x0 = a ' + y

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information