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Proof step 4 from proof tr-null (previous step)

t = branch(t0, a, t1), tr(null, t)(H) ⊦ H = ∅ ∧ t = leaf

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
tr(null, branch(t0, a, t1))(H) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ leaf ≠ branch(t, a, t0); (s)