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Proof step 16 from proof ex1-shiftw (previous step)

((rP(r) -* P))(H), rP(r)(H0), H0 ⊥ H, ∀ r. ((rP(r) -* P))(H) ⊦ P(H0 ∪ H)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ ((P0 -* P1))(H) ↔ (∀ H1. H1 ⊥ H ∧ P0(H1) → P1(H1 ∪ H))
Proof step 18:
rP(r)(H0), H0 ⊥ H, ∀ r. ((rP(r) -* P))(H), ∀ H1. H1 ⊥ H ∧ rP(r)(H1) → P(H1 ∪ H) ⊦ P(H0 ∪ H)

Rule argument

spec: heap-sep name: wand seq: ⊦ ((P0 -* P1))(H) ↔ (∀ H1. H1 ⊥ H ∧ P0(H1) → P1(H1 ∪ H)) subst: [H, P1, P0] → [H, P, rP(r)] flags: <all paths>

Additional information

Used terms: H, P, rP(r)