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Proof step 1 from proof ex2-shiftw (conclusion)

⊦ ((_∃ rrP -* P))(H) ↔ (∀ r0, r1. ((rrP(r0, r1) -* P))(H))

User applied rule case distinction

And obtained the following new goals

Proof step 2:
((_∃ rrP -* P))(H) ⊦ ∀ r0, r1. ((rrP(r0, r1) -* P))(H)
Proof step 12:
∀ r0, r1. ((rrP(r0, r1) -* P))(H) ⊦ ((_∃ rrP -* P))(H)

Rule argument

pos: right 1

Additional information