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Proof step 18 from proof ex2-shiftw (
previous step
)
rrP(r, r0)(H0), H0 ⊥ H, ∀ r0, r1. ((rrP(r0, r1) -* P))(H), ∀ H1. H1 ⊥ H ∧ rrP(r, r0)(H1) → P(H1 ∪ H) ⊦ P(H0 ∪ H)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 4 terms: H0
Additional information
Used terms: H0