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Proof step 12 from proof ex3-shift (previous step)

P(H0), oP(o)(H1), H1 ⊥ H0 ⊦ ((_∃ oP * P))(H1 ∪ H0), (_∃ oP)(H1) ∧ P(H0) ∧ H1 ⊥ H0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
P(H0), oP(o)(H1), H1 ⊥ H0 ⊦ ((_∃ oP * P))(H1 ∪ H0), ∃ o. oP(o)(H1)

Rule argument

Additional information

Used simplifier rules: ex3: ⊦ (_∃ oP)(H) ↔ (∃ o. oP(o)(H));