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Proof step 5 from proof ex3-shiftw (previous step)

((_∃ oP -* P))(H) ⊦ ∀ H1. H1 ⊥ H ∧ oP(o)(H1) → P(H1 ∪ H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
((_∃ oP -* P))(H), oP(o)(H0), H0 ⊥ H ⊦ P(H0 ∪ H)

Rule argument

Additional information