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Proof step 1 from proof mapex-and (conclusion)

⊦ (r =>_ ∧ r => o) = r => o

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (_∃(λ o. r => o) ∧ r => o) = r => o

Rule argument

Additional information

Used simplifier rules: mapex: ⊦ r =>_ = _∃(λ o. r => o);