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Proof step 1 from proof owns-none-one (conclusion)
⊦ owns-none(a, rs, g) ∧ r ∈ rs ∧ r ≠ null → owns-one(a, r, rs, g(r; a))
System applied rule normalize
And obtained the following new goals
Proof step 2
:
owns-none(a, rs, g), r ∈ rs ⊦ r = null, owns-one(a, r, rs, g(r; a))
Rule argument
Additional information