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Proof step 17 from proof owns-one-map (previous step)

r ∈ rs, ∀ r0. r0 ∈ rs ∧ r0 ≠ r → g(r0) ≠ g(r) ⊦ # rs = 0, mk(∅ ++ r, f)[r] = f(r), r = null, rs = ∅

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ r ∈ rs → mk(rs, f)[r] = f(r)

Rule argument

spec: heap-fun name: at-mk seq: ⊦ r ∈ rs → mk(rs, f)[r] = f(r) subst: [r, f, rs] → [r, f, ∅ ++ r] flags: <all paths>

Additional information

Used simplifier rules: ⊦ r ∈ ∅ ++ r0 ↔ r = r0; (s) Used terms: r, f, ∅ ++ r