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Proof step 13 from proof alloc-p (previous step)

r =>_ = !(me, O2, r =>_), rely(me, O1(r; me), H1 ++ r, O2, H2), ∃ H0, H2. H0 ⊥ H2 ∧ H1 ++ r = H0 ∪ H2 ∧ r =>_(H0) ∧ ((!(me, O1, P) * P0))(H2) ⊦ r = null, ((!(me, O2, r =>_ * P) * P0))(H1 ++ r), r ∈ H1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
H1 ++ r = H0 ∪ H, r =>_ = !(me, O2, r =>_), ((!(me, O1, P) * P0))(H), r =>_(H0), rely(me, O1(r; me), H1 ++ r, O2, H2), H0 ⊥ H ⊦ r = null, ((!(me, O2, r =>_ * P) * P0))(H1 ++ r), r ∈ H1

Proof step 13 from proof alloc-p (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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