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Proof step 19 from proof alloc-p (previous step)

H1 ++ r = H0 ∪ H4 ∪ H3, r =>_ = !(me, O2, r =>_), !(me, O1, P)(H4), r =>_(H0), P0(H3), rely(me, O1(r; me), H1 ++ r, O2, H2), H0 ⊥ H3, H0 ⊥ H4, H4 ⊥ H3 ⊦ r = null, (((!(me, O2, r =>_) * !(me, O2, P)) * P0))(H1 ++ r), r ∈ H1

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags:

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