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Proof step 6 from proof alloc-p (previous step)

((r =>_ * !(me, O1, P) * P0))(H1 ++ r) ↔ ((!(me, O1, P) * P0))(H1), ((!(me, O1, P) * P0))(H1), rely(me, O1(r; me), H1 ++ r, O2, H2) ⊦ r = null, ((!(me, O2, r =>_ * P) * P0))(H1 ++ r), r ∈ H1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
((!(me, O1, P) * P0))(H1), ((r =>_ * !(me, O1, P) * P0))(H1 ++ r), rely(me, O1(r; me), H1 ++ r, O2, H2) ⊦ r = null, ((!(me, O2, r =>_ * P) * P0))(H1 ++ r), r ∈ H1

Proof step 6 from proof alloc-p (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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