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Proof step 2 from proof alloc (previous step)

rely(me, O1(r; me), H1 ++ r, O2, H2) ⊦ ((P0 * true))(H1) ↔ ((!(me, O2, r =>_) * P0 * true))(H1 ++ r), r = null, r ∈ H1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information