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Proof step 5 from proof compact-local (previous step)

∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ !(me, O, P0)(H0) ∧ !(me, O, P1)(H1) ⊦ !(me, O, P0 * P1)(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information