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Proof step 32 from proof ex-shift-o-p (previous step)

((oP(o) * P0))(H1), P(H0), H1 ⊥ H0, ∀ r. r ∈ H1 → O(r) = me ⊦ ((!(me, O, _∃ oP * P0) * P))(H1 ∪ H0), ∃ o. ((oP(o) * P0))(H1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: o

Additional information

Used terms: o