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Proof step 2 from proof lift-map (previous step)

⊦ ((r => o))(H) ↔ !(me, O(r; me), r => o)(H)

User applied rule case distinction

And obtained the following new goals

Proof step 3:
((r => o))(H) ⊦ !(me, O(r; me), r => o)(H)
Proof step 8:
!(me, O(r; me), r => o)(H) ⊦ ((r => o))(H)

Rule argument

pos: right 1

Additional information