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Proof step 3 from proof owned-r (previous step)

!(me, O, P)(H), r ∈ H ⊦ O(r) = me

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ !(id, O, P)(H) ↔ P(H) ∧ (∀ r. r ∈ H → O(r) = id)
Proof step 5:
P(H), r ∈ H, ∀ r. r ∈ H → O(r) = me ⊦ O(r) = me

Rule argument

spec: <toplevel> name: owned seq: ⊦ !(id, O, P)(H) ↔ P(H) ∧ (∀ r. r ∈ H → O(r) = id) subst: [H, P, O, id] → [H, P, O, me] flags: <all paths>

Additional information

Used terms: H, P, O, me