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Proof step 3 from proof propagate (previous step)

((!(me, O2, P) * P0))(H1), ((!(id, O2, P1) * true))(H2), rely(me, O1, H1, O2, H2) ⊦ id = me, ((!(me, O2, P) * !(id, O2, P1) * true))(H2)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ((P0 * P1))(H) ↔ (∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P0(H0) ∧ P1(H1))
Proof step 5:
((!(id, O2, P1) * true))(H2), rely(me, O1, H1, O2, H2), ∃ H0, H2. H0 ⊥ H2 ∧ H1 = H0 ∪ H2 ∧ !(me, O2, P)(H0) ∧ P0(H2) ⊦ id = me, ((!(me, O2, P) * !(id, O2, P1) * true))(H2)

Rule argument

spec: heap-sep name: sep seq: ⊦ ((P0 * P1))(H) ↔ (∃ H0, H1. H0 ⊥ H1 ∧ H = H0 ∪ H1 ∧ P0(H0) ∧ P1(H1)) subst: [H, P1, P0] → [H1, P0, !(me, O2, P)] flags: <all paths>

Additional information

Used terms: H1, P0, !(me, O2, P)