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Proof step 8 from proof rely-trans (previous step)

rely(me, O0, H0, O1, H1), ∀ r. (O1(r) = me ↔ O2(r) = me) ∧ (O1(r) = me → (r ∈ H1 ↔ r ∈ H2) ∧ (r ∈ H1 → H1[r] = H2[r])) ⊦ (O0(r) = me ↔ O2(r) = me) ∧ (O0(r) = me → (r ∈ H0 ↔ r ∈ H2) ∧ (r ∈ H0 → H0[r] = H2[r]))

User applied rule all left

And obtained the following new goals

Proof step 9:
O1(r) = me ↔ O2(r) = me, rely(me, O0, H0, O1, H1), O1(r) = me → (r ∈ H1 ↔ r ∈ H2) ∧ (r ∈ H1 → H1[r] = H2[r]) ⊦ (O0(r) = me ↔ O2(r) = me) ∧ (O0(r) = me → (r ∈ H0 ↔ r ∈ H2) ∧ (r ∈ H0 → H0[r] = H2[r]))

Rule argument

pos: left 2 terms: r abort: F discard: T computed: T

Additional information

Used terms: r