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Proof step 15 from proof switch-ownership (previous step)

P(H), r ∈ H, ∀ r0. (O1(r0) = O1(r) ↔ O2(r0) = O1(r)) ∧ (O1(r0) = O1(r) → (r0 ∈ H1 ↔ r0 ∈ H2) ∧ (r0 ∈ H1 → H1[r0] = H2[r0])) ⊦ O2(r) = O1(r)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: r

Additional information

Used terms: r