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Proof step 25 from proof write-known-p (
previous step
)
((r => o0 * P))(H0), P0(H), rely(me, O1, H0[r, o1] ∪ H, O2, H2), r0 ∈ H0, H0 ⊥ H, ∀ r. r ∈ H0 → O2(r) = me ⊦ O2(r0) = me, ((!(me, O2, r => o1 * P) * P0))(H0[r, o1] ∪ H)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 6 terms: r0
Additional information
Used terms: r0