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Proof step 36 from proof write-known-p (previous step)

H1[r, o1] = H0 ∪ H, ((r => o1 * P))(H0), P0(H), rely(me, O1, H1[r, o1], O2, H2), r ∈ H1, H0 ⊥ H, ∀ r. r ∈ H0 → O2(r) = me ⊦ ∃ H3, H4. H3 ⊥ H4 ∧ H1 = H3 ∪ H4 ∧ !(me, O2, r => (H3 ∪ H4)[r] * P)(H3) ∧ P0(H4)

User applied rule exists right

And obtained the following new goals

Proof step 37:
H1[r, o1] = H0 ∪ H, ((r => o1 * P))(H0), P0(H), rely(me, O1, H1[r, o1], O2, H2), r ∈ H1, H0 ⊥ H, ∀ r. r ∈ H0 → O2(r) = me ⊦ H0[r, H1[r]] ⊥ H ∧ H1 = H0[r, H1[r]] ∪ H ∧ !(me, O2, r => (H0[r, H1[r]] ∪ H)[r] * P)(H0[r, H1[r]]) ∧ P0(H)

Rule argument

pos: right 1 terms: H0[r, H1[r]], H abort: F discard: T computed: F

Additional information

Used terms: H0[r, H1[r]], H