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Proof step 4 from proof max-sum-empty-array (
previous step
)
⊦ ∃ n, m. n + m = 0 ∧ 0 = sum(mkarray(0), n, m) ∧ upper-bound(mkarray(0), 0)
User applied rule exists right
And obtained the following new goals
Proof step 5
:
⊦ 0 + 0 = 0 ∧ 0 = sum(mkarray(0), 0, 0) ∧ upper-bound(mkarray(0), 0)
Rule argument
pos: right 1 terms: 0, 0 abort: F discard: T computed: F
Additional information
Used terms: 0, 0