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Proof step 1 from proof sum-subarray (conclusion)
m0 + m1 ≤ n, n ≤ # ar ⊦ sum(subarray(ar, 0, n), m0, m1) = sum(ar, m0, m1)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
n ≤ # ar, m0 + m1 ≤ n ⊦ sum(subarray(ar, 0, n), m0, m1) = sum(ar, m0, m1)
Rule argument
Additional information