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Proof step 4 from proof sum-subarray (previous step)

m0 + m < n, m0 + m < # ar, n ≤ # ar, ∀ n, ar, m0. n ≤ # ar ∧ m0 + m ≤ n → sum(subarray(ar, 0, n), m0, m) = sum(ar, m0, m) ⊦ sum(subarray(ar, 0, n), m0, m) = sum(ar, m0, m)

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: n, ar, m0 abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s) Used terms: n, ar, m0