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Proof step 4 from proof kadane-correct (previous step)

max_ending_here = 0, max_so_far = 0, n = 0, size = # a ⊦ 0 ≤ max_ending_here ∧ max_ending_here ≤ max_so_far ∧ n ≤ size ∧ maximum-sum(subarray(a, 0, n), max_so_far) ∧ (∃ m. maximum-suffix-sum(subarray(a, 0, n), m, max_ending_here))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ ∃ m. maximum-suffix-sum(mkarray(0), m, 0)

Rule argument

Additional information

Used simplifier rules: ⊦ maximum-sum(mkarray(0), 0); (s)% ⊦ subarray(ar0, n, 0) = mkarray(0); (s)% ⊦ 0 ≤ m; (s)