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Proof step 1 from proof sorted-next-0-swap (conclusion)

n + 1 < # x ⊦ partial-sorted(x, 0, n) ∧ x[n + 1] < x[n] ∧ n % 2 = 0 → partial-sorted(x[n, x[n + 1]][n + 1, x[n]], 0, n + 2)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information