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Proof step 18 from proof sorted-next-0-swap (previous step)

n % 2 = 0, 2 * n0 + 1 < # x, 2 * n0 < n, x[n + 1] < x[n], x[1 + 2 * n0] < x[2 * n0], n < # x, n + 1 < # x, 2 * n0 < # x, 2 * n0 + 1 < n, 2 + 2 * n0 < # x, ∀ n0. 1 + 2 * n0 < n → ¬ x[1 + 2 * n0] < x[2 * n0] ⊦ n + 1 = 2 * n0, x[n, x[n + 1]] = [], n = 1 + 2 * n0, n = 2 * n0, x = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 11 terms: n0

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic Used terms: n0