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Proof step 1 from proof sorted-next-0 (conclusion)

⊦ partial-sorted(x, 0, n) ∧ ¬ x[n + 1] < x[n] ∧ n % 2 = 0 → partial-sorted(x, 0, n + 2)

System applied rule normalize

And obtained the following new goals

Proof step 2:
n % 2 = 0, partial-sorted(x, 0, n) ⊦ x[n + 1] < x[n], partial-sorted(x, 0, n + 2)

Rule argument

Additional information