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Proof step 3 from proof sorted-next-0 (previous step)

n % 2 = 0, x[1 + 2 * n0] < x[2 * n0], 2 * n0 ≤ n, ∀ n0. 1 + 2 * n0 < n → ¬ x[1 + 2 * n0] < x[2 * n0] ⊦ x[n + 1] < x[n]

User applied rule all left

And obtained the following new goals

Proof step 4:
n % 2 = 0, x[1 + 2 * n0] < x[2 * n0], 2 * n0 ≤ n, 1 + 2 * n0 < n → ¬ x[1 + 2 * n0] < x[2 * n0] ⊦ x[n + 1] < x[n]

Rule argument

pos: left 4 terms: n0 abort: F discard: T computed: T

Additional information

Used terms: n0