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Proof step 20 from proof count-mkbag-greater-one (previous step)

A[m] = A[i0], A[n] = A[i0], count(A[i0], mkbag(A, i0)) = 0, m < i0, n < # A, m < # A, i0 < # A, m + 1 < # A, 2 ≤ # A, n ≤ i0 ⊦ i0 = m, m = n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
n < i, i ≤ # A, A[n] = a ⊦ count(a, mkbag(A, i)) ≠ 0

Rule argument

spec: <toplevel> name: count-mkbag-non-zero seq: n < i, i ≤ # A, A[n] = a ⊦ count(a, mkbag(A, i)) ≠ 0 subst: [n, i, A, a] → [m, i0, A, A[i0]] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s) Used terms: m, i0, A, A[i0]