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Proof step 16 from proof count-mkbag-greater-two (previous step)

1 = count(A[i0], mkbag(A, i0)), A[m1] = A[i0], A[m0] = A[i0], A[m] = A[i0], i0 < # A, m0 < # A, m < # A, m1 < # A, m0 ≤ i0, m ≤ i0, m1 ≤ i0 ⊦ m = m1, m = m0, m0 = m1

User applied rule cut formula

And obtained the following new goals

Proof step 17:
1 = count(A[i0], mkbag(A, i0)), A[m] = A[i0], A[m0] = A[i0], A[m1] = A[i0], m1 < # A, m < # A, m0 < # A, i0 < # A, m < i0, m1 ≤ i0, m ≤ i0, m0 ≤ i0 ⊦ m = m0, m = m1, m0 = m1
Proof step 25:
1 = count(A[i0], mkbag(A, i0)), A[m] = A[i0], A[m0] = A[i0], A[m1] = A[i0], m1 < # A, m < # A, m0 < # A, i0 < # A, m1 ≤ i0, m ≤ i0, m0 ≤ i0 ⊦ m = m0, m = m1, m0 = m1, m < i0

Rule argument

fma: m < i0

Additional information

Used formulas: m < i0