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Proof step 2 from proof count-mkbag-non-zero (previous step)

A[n] = a, count(a, mkbag(A, i)) = 0, n < i, i ≤ # A ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
count(A[n], mkbag(A, i)) = 0, n < i, n < # A, i ≤ # A ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic