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Proof step 8 from proof count-mkbag-non-zero (previous step)

count(A[n], mkbag(A, i0)) = 0, n < # A, i0 < # A, n ≤ i0, ∀ A0, n0. count(A0[n0], mkbag(A0, i0)) ≠ 0 ∨ ¬ n0 < i0 ∨ ¬ n0 < # A0 ∨ ¬ i0 ≤ # A0 ⊦ A[n] = A[i0]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: A, n

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: A, n