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Proof step 11 from proof in-mkbag-del-two (
previous step
)
A[m] = A[n], A[n0] = A[n], count(A[n], mkbag(A, i)) = 0, n0 < # A, n < # A, m < # A, n0 < i, n < i, m < i, i ≤ # A ⊦ n = m, n = n0, n0 = m
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 12
:
n < i, i ≤ # A, A[n] = a ⊦ count(a, mkbag(A, i)) ≠ 0
Rule argument
spec: <toplevel> name: count-mkbag-non-zero seq: n < i, i ≤ # A, A[n] = a ⊦ count(a, mkbag(A, i)) ≠ 0 subst: [n, i, A, a] → [n0, i, A, A[n]] flags: <all paths>
Additional information
Used terms: n0, i, A, A[n]