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Proof step 41 from proof in-mkbag-del-two (previous step)

A[m] = A[n], count(A[n], mkbag(A, i)) = m0 + 1, m0 = 0, m < i, n < i, n0 < i, m < # A, n < # A, n0 < # A, i ≤ # A ⊦ A[n] = A[n0], count(A[n], mkbag(A, i)) = 0, n = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
A[m] = A[n], count(A[n], mkbag(A, i)) = 1, m < i, n < i, n0 < i, m < # A, n < # A, n0 < # A, i ≤ # A ⊦ A[n] = A[n0], n = m

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic